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x^2-2/3x=1/3
We move all terms to the left:
x^2-2/3x-(1/3)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
x^2-2/3x-(+1/3)=0
We get rid of parentheses
x^2-2/3x-1/3=0
We calculate fractions
x^2=0
a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{2}=0$
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